18X^2+3x=15

Solution for 18X^2+3x=15 equation:

18X^2+3X=15

We move all terms to the left:

18X^2+3X-(15)=0

a = 18; b = 3; c = -15;
Δ = b2-4ac
Δ = 32-4·18·(-15)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*18}=\frac{-36}{36}
=-1
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*18}=\frac{30}{36}
=5/6
$